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add a function to get the highest ACK range in receivedPacketHistory

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This commit is contained in:
Marten Seemann
2017-01-08 19:36:59 +07:00
parent 7fc9d59381
commit 634d2dc6b7
2 changed files with 29 additions and 0 deletions
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10
ackhandler/received_packet_history.go
View File

@@ -133,3 +133,13 @@ func (h *receivedPacketHistory) GetAckRanges() []frames.AckRange {
return ackRanges return ackRanges
} }
func (h *receivedPacketHistory) GetHighestAckRange() frames.AckRange {
ackRange := frames.AckRange{}
if h.ranges.Len() > 0 {
r := h.ranges.Back().Value
ackRange.FirstPacketNumber = r.Start
ackRange.LastPacketNumber = r.End
}
return ackRange
}

19
ackhandler/received_packet_history_test.go
View File

@@ -315,4 +315,23 @@ var _ = Describe("receivedPacketHistory", func() {
Expect(ackRanges[2]).To(Equal(frames.AckRange{FirstPacketNumber: 1, LastPacketNumber: 2})) Expect(ackRanges[2]).To(Equal(frames.AckRange{FirstPacketNumber: 1, LastPacketNumber: 2}))
}) })
}) })
Context("Getting the highest ACK range", func() {
It("returns the zero value if there are no ranges", func() {
Expect(hist.GetHighestAckRange()).To(BeZero())
})
It("gets a single ACK range", func() {
hist.ReceivedPacket(4)
hist.ReceivedPacket(5)
Expect(hist.GetHighestAckRange()).To(Equal(frames.AckRange{FirstPacketNumber: 4, LastPacketNumber: 5}))
})
It("gets the highest of multiple ACK ranges", func() {
hist.ReceivedPacket(3)
hist.ReceivedPacket(6)
hist.ReceivedPacket(7)
Expect(hist.GetHighestAckRange()).To(Equal(frames.AckRange{FirstPacketNumber: 6, LastPacketNumber: 7}))
})
})
}) })